20=17t-5t^2

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Solution for 20=17t-5t^2 equation: 



20=17t-5t^2

We move all terms to the left:

20-(17t-5t^2)=0

We get rid of parentheses

5t^2-17t+20=0

a = 5; b = -17; c = +20;
Δ = b2-4ac
Δ = -172-4·5·20
Δ = -111
Delta is less than zero, so there is no solution for the equation

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